PowerPoint - Redox Introduction, Assigning Oxidation Numbers

PowerPoint - Redox Introduction, Assigning Oxidation Numbers

Unit 7: Redox & Electrochemistry Whats the point ? REDOX reactions are important in Purifying metals (e.g. Al, Na, Li) C3H8O + CrO3 + H2SO4 Cr2(SO4)3 + C3H6O + H2O Producing gases (e.g. Cl2, O2, H2)

Electroplating metals Electrical production (batteries, fuel cells) Protecting metals from corrosion Balancing complex chemical equations Sensors and machines (e.g. pH meter) What is Redox? REDOX stands for REDuction/OXidation Oxidation is often thought of as a combination of a substance with oxygen (rusting, burning) Just like with acid/base definitions the definition of oxidation is expanded Oxidation refers to a loss of electrons

Reduction refers to a gain of electrons As a mnemonic remember LEO says GER Loss Electrons = Oxidation Gain Electrons = Reduction Read 12.1 (pg. 443 - 445) Testing concepts Q- What is oxidation? What is reduction? Represent each as a chemical equation. A- oxidation = loss of e X X+ + e reduction = gain of e X + e X Q- Why are 2Na + Cl2 2NaCl & 2H2 + O2 H2O considered redox reactions? A- Both involve the transfer of electron density (Na has

no charge, the atoms in diatomic molecules have no partial charge. After reaction the atoms have different shares of the electrons because of different EN values) Q- Is it possible to oxidize a material without reducing something else? A- No. A lost e is taken up by something else. Testing concepts Q- Define oxidizing agent, reducing agent. A- An oxidizing agent causes oxidation by being reduced itself A reducing agent causes reduction by being

oxidized itself Q- PE 1 A- CaCl2 is an ionic compound with a positive calcium ion and negative chlorine ions Ca + Cl2 CaCl2 Ca Ca2+ + 2e, Cl2 + 2e 2Cl. Thus Ca is losing electrons (oxidation) and Cl is gaining electrons (reduction). These are called half reactions Oxidation numbers We will see that there is a simple way to keep track of oxidation and reduction This is done via oxidation numbers

An oxidation number is the charge an atom would have if electrons in its bonds belonged completely to the more electronegative atom E.g. in HCl, Cl has a higher EN (pg. 255). Thus, oxidation numbers are Cl = -1, H = +1 Notice that oxidation numbers are written as +1 vs. 1+ to distinguish them from charges. Instead of referring to EN chart, a few rules are followed to assign oxidation numbers Refer also to study note Rules (and rationale - 12.2) 1. Any element, when not combined with atoms of a different element, has an oxidation # of zero. (O in O2 is zero)

2. Any simple monatomic ion (one-atom ion) has an oxidation number equal to its charge (Na+ is +1, O2 is 2) 3. The sum of the oxidation numbers of all of the atoms in a formula must equal the charge written for the formula. (if the oxidation number of O is 2, then in CO32 the oxidation number of C is +4) Rules (and rationale - 12.2) 4. In compounds, the oxidation # of IA metals is +1, IIA is +2, and aluminum (in IIIA) is +3 5. In ionic compounds, the oxidation # of a nonmetal or polyatomic ion is equal to the charge of its associated ion. (CuCl 2, Cl is 1) 6. F is always 1, O is always 2 (unless combined with F), H is usually

+1 rule total Ox.# or rule 5 6 3 6 4 3 6 3 6 6 3 5 6 3 6 +1 +5 -6 +2 +12 -14 -4 +6 -2 +1 -1 +2 +5 -8 +1 +5 -2 +1 +6 -2 -2 +1 -2 +1 -1 +1 +5 -2 H N O3 K2Cr2O7 C2H6O AgI H2PO4 PE 2 (450), 12.9, 12.12 (484), 12.10, 12.11, 12.13 (484) More practice

PE 2 pg. 450: answers in back of book 12.9, 12.12 (pg. 484): answers in back of book 12.10: a) Cl=+7, b) Cr=+3, c) Sn=+4, d) Au=+3 12.11: a) Na= +1, H = +1, P= +5, O= -2 b) Ba= +2, Mn= +6, O= -2 c) Na= +1, S= +2.5, O= -2 d) Cl= +3, F= -1 12.13: a) +2, b) +4, c) +3, d) +5, e) -2, f) 0, g) 1, h) -3 I) 1/3 For more lessons, visit www.chalkbored.com

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